Python 2.7.3 (default, Aug 1 2012, 05:16:07)
[GCC 4.6.3] on linux2
Type "help", "copyright", "credits" or "license" for more information.
# Let's create an array using a list data structure
>>> array = []
>>> array.append(1)
>>> array.append(2)
>>> array.append(4)
>>> array.append(8)
# Let's display this array
>>> print array
[1, 2, 4, 8]
# Printing elements at a specified index in the array
>>> print array[3]
8
# Let's modify what we stored at Index 3
>>> array[3] = 10
>>> print array
[1, 2, 4, 10]
# Let's create a second array
>>> secondArray = [1,2,3]
>>> print array + secondArray
# An array formed by concatenating the two arrays
[1, 2, 4, 10, 1, 2, 3]
# Now, let's create a third array
>>> thirdArray = [10,98,1,2,4,2,0]
# This is how we sort an array
>>> thirdArray.sort()
>>> print thirdArray
[0, 1, 2, 2, 4, 10, 98]
# This is how we find the index of a particular element in the array
>>> print thirdArray.index(1)
1
>>> print thirdArray.index(999)
# If we look for an element which is not present in the list, we get an error of this kind
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
ValueError: 999 is not in list
# So here is what we can do instead
>>> if 999 in thirdArray: print thirdArray.index(999)
...
# Now, let's look for another element which is known to be in this array'
>>> if 2 in thirdArray: print thirdArray.index(2)
...
2
# How can we create 2D arrays in Python? Answer: We use a list of lists
>>> array2DTest = []
>>> array2DTest += [[1,2,3]]
>>> print array2DTest
[[1, 2, 3]]
>>> array2DTest += [[1,4,6]]
>>> print array2DTest
[[1, 2, 3], [1, 4, 6]]
>>> array2DTest[0]
[1, 2, 3]
>>> array2DTest[1]
[1, 4, 6]
>>> array2DTest[1][2]
6
>>> array2DTest[0][0]
1
# A quick look at what zipping a pair of lists does. It returns a list of tuples of (n-th member of first list, n-th member of second list)
>>> zip([1,2,3,4],[5,6,7,8])
[(1, 5), (2, 6), (3, 7), (4, 8)]
>>> exit
Use exit() or Ctrl-D (i.e. EOF) to exit
>>>
