262nd Number in the Lucas Number Sequence = 4114000911454431885883343305337966369078499341559272017 In general, the nth term is given by f(n-1)+f(n-2) To understand this sequence and how it differs from the Fibonacci series, you might find it useful to read the Lucas Sequence tutorial over here. |
|
Comparing Indian Boards Queries: School Performance Rankings
A list of CBSE Toppers from schools all over India A list of CBSE's top performing schools (Class 12) A list of CBSE's top performing schools (Class 10) CBSE RESULT 2018
Popular Universities The DU Admission Mess
School Performance Rankings (Old)
Moderation Mess
Career Paths
Info for parents and students
looking for schools and admissions.
DISE Data for School Infrastructure
Python for Data R for Data
Old CBSE Results
General Posts
Popular articles
Mathematics
Basics
Quizzes on ProgressionsMCQ #1: Arithmetic Progression MCQ #2: Geometric Progression MCQ #3 : More on Geometric Progressions. Polynomial Curves
|
|